Combined solids, conversions, frustum — Class 10 ka complete mensuration chapter.
🌟 Kyun Zaroori Hai?
🏭 Real Life Applications:
• Ice cream cone mein cone + hemisphere = volume of ice cream
• Water tank (cylinder) mein kitna paani? → Volume
• Gift box wrap karne ke liye paper kitna chahiye? → Surface area
• Candle jo cone hai, cylinder par rakhkha — material cost kya? → SA + Volume
📋 All Formulas — Quick Reference
🟫 Cuboid
l = length, b = breadth, h = height
TSA = 2(lb+bh+hl)
LSA = 2(l+b)h
V = lbh
🟦 Cube
Side = a
TSA = 6a²
LSA = 4a²
V = a³
🔴 Cylinder
r = radius, h = height
TSA = 2πr(r+h)
CSA = 2πrh
V = πr²h
🔺 Cone
r = base radius, h = height
l = slant = √(r²+h²)
TSA = πr(r+l)
CSA = πrl
V = (1/3)πr²h
⚽ Sphere
r = radius
TSA = 4πr²
V = (4/3)πr³
🔵 Hemisphere
r = radius
TSA = 3πr²
CSA = 2πr²
V = (2/3)πr³
🔗 Combined Solids — Surface Area
Key Rule: Combined solid ka TSA = visible surfaces ka sum ONLY.
Jahan do shapes join hote hain wahan ki surfaces count NAHI hoti (woh andar hain)!
Example 1: Capsule = Cylinder + 2 Hemispheres (medicine capsule)
Example 2: Cone on top of cylinder (r=3, cone h=4, cylinder h=8). TSA aur Volume.
Slant of cone: l = √(9+16) = 5 cm
TSA = πrl (cone lateral) + 2πrh (cylinder lateral) + πr² (bottom circle) Note: top circle of cylinder = base of cone → not counted in SA
TSA = π×3×5 + 2π×3×8 + π×9 = 15π + 48π + 9π = 72π ≈ 226.19 cm²
Q1. Solid hemisphere ka radius 7 cm hai. TSA nikalo. (π=22/7)
TSA = 3πr² = 3×(22/7)×49 = 462 cm²
Q2. Ek cone ka radius 6 cm aur slant height 10 cm. TSA nikalo.
TSA = πr(r+l) = π×6×(6+10) = 96π ≈ 301.59 cm²
Q3. Ek cylinder (r=5, h=14) ke andar exactly ek sphere aur ek cone fit hote hain (same r). Sphere aur cone ki volume, cylinder ki volume se compare karo.
Cylinder V = π×25×14 = 350π. Sphere r=5: V=(4/3)π×125=500π/3. Cone r=5,h=14: V=(1/3)×25π×14=350π/3. Sum = (500+350)π/3=850π/3 ≈ 0.81×350π. Together about 81% of cylinder. Note: A sphere inscribed in cylinder: r=5, h=10 for sphere. This problem needs specific shape constraints.
Q4. Ek metallic cone (r=4.2, h=2.1) ko melt karke spheres (r=0.21cm) banao. Kitne spheres?
Cone V = (1/3)×π×4.2²×2.1 = (1/3)×π×18.522×2.1 = 12.965π cm³
Sphere V = (4/3)π×0.21³ = (4/3)π×0.009261 = 0.01235π cm³
Number = 12.965/0.01235 = 1050 spheres