Sample data se population ke baare mein conclusions nikaalein
Population = sare elements ka set. Sample = population ka ek subset. Inferential statistics mein sample se population ke baare mein conclusions nikalte hain.
| Method | Description | Use Case |
|---|---|---|
| Simple Random | Har element equal chance | Homogeneous population |
| Stratified | Groups/strata se proportional | Non-homogeneous population |
| Systematic | Har kth element choose karo | Sequential data |
| Cluster | Random groups choose karo | Geographically spread data |
Population parameter (like μ) ka interval estimate jo confidence level ke saath diya jaata hai.
Sample: n=100, x̄=75, σ=10. 95% CI for μ?
Margin of error = z × σ/√n = 1.96 × 10/√100 = 1.96 × 1 = 1.96
CI = (75−1.96, 75+1.96) = (73.04, 76.96)
Matlab: 95% confident hai ki population mean 73.04 aur 76.96 ke beech hai
Statistical claims test karna with evidence from sample data.
| H₀ True | H₀ False | |
|---|---|---|
| Reject H₀ | Type I Error (α) ❌ | Correct ✅ |
| Accept H₀ | Correct ✅ | Type II Error (β) ❌ |
Claim: μ = 500g. Sample: n=36, x̄=492g, σ=24g. Test at α=0.05 (two-tailed).
H₀: μ=500, H₁: μ≠500
z = (492−500)/(24/√36) = −8/4 = −2
|z|=2 > 1.96 → Reject H₀
Conclusion: Significant evidence hai ki μ ≠ 500g
Data: (1,3), (2,5), (3,4), (4,7), (5,9)
n=5, Σx=15, Σy=28, Σx²=55, Σxy=96
b = (5×96 − 15×28)/(5×55 − 15²) = (480−420)/(275−225) = 60/50 = 1.2
a = 28/5 − 1.2×15/5 = 5.6 − 3.6 = 2
Regression line: ŷ = 2 + 1.2x
Predict y at x=6: ŷ = 2 + 1.2×6 = 9.2