Kab ek function "smooth" hai? Kab differentiate kar sakte hain? Yahan sab samajhte hain!
Ek car ka speedometer jo value dikha raha hai — woh speed function ki derivative hai position function ki. Aur agar speedometer ka reading suddenly jump kare (discontinuous ho) — toh physically kya hoga? Car ek jagah se doosri jagah teleport ho jaayegi — jo impossible hai! Isliye real physical functions continuous hote hain. Calculus mein hum formally define karte hain ki "continuous" ka kya matlab hai — aur phir differentiation explore karte hain.
f(x) is continuous at x = a iff:
(i) f(a) defined ho (value exist kare)
(ii) lim[x→a] f(x) exist kare (left limit = right limit)
(iii) lim[x→a] f(x) = f(a) (limit = function value)
f(x) differentiable at x=a iff: f'(a) = lim[h→0] [f(a+h)-f(a)]/h exist kare (finite ho).
Key Rule: Differentiable ⟹ Continuous. But Continuous ⟹ Differentiable NAHI! (Example: |x| at x=0 — continuous hai lekin differentiable nahi!)
Jab function mein variable dono base aur exponent mein ho (jaise xˣ, xsin(x)) — tab log le lo pehle!
Differentiate both sides w.r.t. x: 2x + 2y(dy/dx) = 0
dy/dx = -x/y
Q1. Differentiate y = sin(e^(x²)) w.r.t. x.
Chain rule twice: dy/dx = cos(e^(x²)) × e^(x²) × 2x = 2x·e^(x²)·cos(e^(x²))
Q2. Find dy/dx if y = tan⁻¹(x/(1-x²)).
Hint: x/(1-x²) = ... use substitution x=tan θ. Answer: 2/(1+x²)
Q3. If y = (sin x)ˢⁱⁿˣ, find dy/dx.
ln y = sin x · ln(sin x). Differentiate: (1/y)dy/dx = cos x·ln(sin x) + sin x·(cos x/sin x) = cos x(ln(sin x)+1). dy/dx = (sin x)^(sin x)·cos x·(ln sin x + 1)