Kai Raaste 🛣️
Parallel ka matlab hai: saare components ke dono sire ek hi jodi bindu se jude hain. Ab current ke paas kai raaste hain — wo bat kar sab mein jaata hai.
📌 Parallel ke do sunehre niyam (series ke bilkul ulte):
1️⃣ Voltage har branch par SAME hota hai
V = V₁ = V₂ = V₃
2️⃣ Current BAT jaata hai — sab branches jodkar kul current
I = I₁ + I₂ + I₃
Aur inse nikalta hai:
1/Rp = 1/R₁ + 1/R₂ + 1/R₃
🎯 Do zaroori patterns:
1️⃣ Sabse chhota resistor sabse zyada current leta hai. Kyunki V same hai aur
I = V/R — toh chhota R matlab bada I. (Upar dekho: 5 Ω ne 2.4 A liya, 30 Ω ne sirf 0.4 A.)
2️⃣ Rp hamesha sabse CHHOTE resistor se bhi kam hota hai! Upar
Rp = 3 Ω hai, jo 5, 10, 30 — teeno se kam hai.
Kyun? Kyunki ek aur raasta jodne ka matlab hai current ke liye
aur jagah ban gayi — toh kul rukaawat ghat gayi. Parallel
resistance ghataane ka tareeka hai.
Ek hall se bahar nikalne ka ek darwaza ho toh bheed lagti hai.
Ab teen darwaze khol do. Log bat jaayenge, aur bahar nikalna
aasaan ho jaayega — yani kul rukaawat ghat gayi.
Aur agar ek darwaza sabse chauda ho? Sabse zyada log wahin se nikalenge — bilkul
jaise sabse chhota resistor sabse zyada current leta hai.
Aur ek darwaza band ho jaaye? Baaki do se log phir bhi nikal sakte hain —
yahi parallel ka sabse bada faayda hai.
🧮 Hal Kiye Hue Sawaal
5 Ω, 10 Ω aur 30 Ω parallel mein 12 V se jude hain. Nikaalo:
(a) kul resistance (b) har branch ka current (c) kul current.
Step 1 — kul resistance:
1/Rp = 1/5 + 1/10 + 1/30
LCM 30 lo: = 6/30 + 3/30 + 1/30 = 10/30
1/Rp = 1/3 → Rp = 3 Ω
⚠️ Yahan sabse badi galti hoti hai: log 10/30 nikaal kar wahin ruk jaate hain aur
R = 10/30 likh dete hain. ULTA (reciprocal) karna mat bhoolo!
Step 2 — har branch ka current (har par poora 12 V):
I₁ = 12/5 = 2.4 A
I₂ = 12/10 = 1.2 A
I₃ = 12/30 = 0.4 A
Step 3 — kul current (do tareeke, dono se same aana chahiye):
Tareeka A: I = I₁ + I₂ + I₃ = 2.4 + 1.2 + 0.4 = 4 A
Tareeka B: I = V/Rp = 12/3 = 4 A ✓
✅ Dono mel khaate hain — jawab sahi hai.
Do 6 Ω ke resistor parallel mein. Kul resistance?
Hal: 1/R = 1/6 + 1/6 = 2/6 = 1/3 → R = 3 Ω
💡 Shortcut: do barabar R parallel mein =
R/2. Aur n barabar R parallel mein = R/n.
Jaise chaar 8 Ω parallel mein = 8/4 = 2 Ω.
Aur sirf do alag resistor ke liye ye formula tez hai:
R = (R₁ × R₂) / (R₁ + R₂)
Ek 2 Ω ka resistor, do 4 Ω ke parallel jode ke saath
series mein hai. Poora circuit 12 V se juda hai. Sab
nikaalo.
Step 1 — pehle PARALLEL wala hissa hal karo (hamesha andar se bahar
chalo):
4 Ω || 4 Ω = 4/2 = 2 Ω
Step 2 — ab wo 2 Ω, baaki 2 Ω ke SERIES mein hai:
Rtotal = 2 + 2 = 4 Ω
Step 3 — kul current:
I = V/R = 12/4 = 3 A
Step 4 — voltage kaise bata:
2 Ω wale par: V = 3 × 2 = 6 V
Parallel jode par: V = 3 × 2 = 6 V (ya 12 − 6 = 6 V)
Step 5 — har 4 Ω mein current (dono par 6 V):
I = 6/4 = 1.5 A har ek mein
✅ Jaanch: 1.5 + 1.5 = 3 A = kul current ✓
(a) 2 Ω aur 3 Ω parallel mein. Rp = ?
Jawab: R = (2×3)/(2+3) = 6/5 =
1.2 Ω
(b) Teen 12 Ω ke resistor parallel mein. Rp = ?
Jawab: 12/3 = 4 Ω
(c) Upar wale (b) ko 6 V se jodo. Kul current?
Jawab: I = 6/4 = 1.5 A
🏠 Ghar Ki Wiring Parallel Mein Hi Kyun?
| Series | Parallel | |
|---|---|---|
| Current | Har jagah same | Bat jaata hai |
| Voltage | Bat jaata hai | Har branch par same |
| Kul resistance | R₁ + R₂ + R₃ (badhta) | 1/R = 1/R₁ + 1/R₂ (ghatta) |
| Ek device kharab ho toh | Sab band | Baaki chalte rehte hain |
| Alag switch | Nahi ho sakta | Ho sakta hai |
| Har device ko poora voltage | Nahi milta | Milta hai |
| Kahan use hota hai | Fuse, switch, ammeter | Ghar ki poori wiring |
🏠 Ghar mein parallel hi kyun — teen pakke kaaran:
1️⃣ Har upkaran ko poora 220 V milta hai. Bulb, TV, fridge — sabko wahi voltage
chahiye jiske liye wo bane hain.
2️⃣ Har cheez ka apna switch. Aap pankha band karke bulb jala sakte ho.
3️⃣ Ek kharab, baaki theek. Ek bulb fuse hua toh poora ghar andhere mein nahi
doobta.
⚠️ Par ek dhyaan dene wali baat: jitne zyada upkaran parallel mein jodoge, kul
current utna badhta jaayega (kyunki Rp ghat raha hai). Isiliye har
ghar mein fuse ya MCB lagta hai — jo current zyada hote hi line
kaat deta hai.
Bharat ke gaon-dehat mein aksar ek hi socket se
extension board par board jodkar kai cheezein chala li jaati hain. Ab aap
physics se samajh sakte ho ki khatra kahan hai.
Har naya upkaran parallel mein judta hai. Har baar Rp
ghatta hai, aur kul current badhta hai. Taar ki apni ek
seema hoti hai — usse zyada current gaya toh H = I²Rt ke hisaab se wo
garam hoga, phir uska plastic cover pighlega, aur phir
short circuit aur aag.
Isiliye:
🔹 Ek socket par zyada bhaari upkaran (heater, geyser, iron) ek saath mat
chalao
🔹 MCB ko kabhi bypass mat karo — wo aapki suraksha hai, rukaawat nahi
🔹 Agar taar garam lag raha hai, toh wo saaf chetavani hai
National Crime Records Bureau ke aankdon ke mutabik bharat mein aag lagne ke
sabse bade kaarnon mein short circuit upar hai. Ye lesson sirf marks ke liye
nahi hai.
🧠 Apne Aap Ko Test Karo
🧮 Numerical Trainer mein series, parallel aur mixed — teeno tarah ke sawaal hal karo!
Start Practice →