Ek Hi Raasta 🛤️
Series ka matlab hai: saare components ek hi line mein, ek ke baad ek jude hain. Current ke paas sirf ek raasta hai — use har component se guzarna hi padega.
📌 Series ke do sunehre niyam:
1️⃣ Current har jagah SAME hota hai
I = I₁ = I₂ = I₃
2️⃣ Voltage BAT jaata hai — sab drops jodkar supply ke barabar
V = V₁ + V₂ + V₃
Aur inse nikalta hai:
Rs = R₁ + R₂ + R₃
Ek hi pipe mein paani bah raha ho. Pipe ke beech mein aap teen alag jagah par
rukaawat laga do.
🔹 Har rukaawat se utna hi paani guzrega — kyunki paani ke paas doosra raasta hai
hi nahi. (current same)
🔹 Par har rukaawat par dabaav (pressure) thoda-thoda girega, aur teeno ke
girawat jodkar poora dabaav ban jaayega. (voltage bat jaata hai)
Aur teen rukaawatein milkar ek badi rukaawat ki tarah kaam karti hain — isiliye
resistance jud jaate hain.
🎯 Ek zaroori pattern: series mein sabse bade resistor par
sabse zyada voltage girta hai. Kyun? Kyunki V = IR, aur I toh sab jagah same hai —
toh V seedha R par nirbhar karta hai.
Aur Rs hamesha sabse bade resistor se bhi zyada hota hai. Series
resistance badhaane ka tareeka hai.
🧮 Hal Kiye Hue Sawaal
5 Ω, 10 Ω aur 15 Ω series mein 30 V ki battery se jude hain.
Nikaalo: (a) kul resistance (b) current (c) har resistor par voltage.
Step 1 — kul resistance:
Rs = 5 + 10 + 15 = 30 Ω
Step 2 — current (poore circuit ke liye Ohm's law):
I = V / Rs = 30 / 30 = 1 A
Step 3 — har resistor par voltage (wahi current, alag R):
V₁ = I × R₁ = 1 × 5 = 5 V
V₂ = I × R₂ = 1 × 10 = 10 V
V₃ = I × R₃ = 1 × 15 = 15 V
✅ Jaanch: 5 + 10 + 15 = 30 V = poori battery ✓
Ye jaanch hamesha karo — agar drops jodkar supply na banein toh kahin galti hai.
3 Ω aur 6 Ω series mein 9 V se jude hain. Sab
nikaalo.
Jawab:
Rs = 3 + 6 = 9 Ω
I = 9/9 = 1 A
V across 3 Ω = 1 × 3 = 3 V • V across 6 Ω = 1 × 6 =
6 V
Jaanch: 3 + 6 = 9 V ✓
Do resistor series mein hain. Kul resistance 12 Ω hai, aur ek resistor
4 Ω ka hai. Doosra kitne ka hai?
Hal: Rs = R₁ + R₂
12 = 4 + R₂ → R₂ = 8 Ω
⚠️ Series Ke Nuksaan
Series jodna aasaan hai — par ghar mein aisa kabhi nahi kiya jaata. Kyun?
❌ Teen badi dikkatein:
1️⃣ Ek toota toh sab band. Current ka ek hi raasta hai — usme kahin bhi break aaya
toh poora circuit band. Ek bulb fuse hua, saare bulb bujh gaye!
2️⃣ Alag-alag control nahi. Ek hi switch sab kuch chalata hai. Aap sirf pankha
band karke bulb nahi jala sakte.
3️⃣ Har cheez ko poora voltage nahi milta. Voltage bat jaata hai — toh 220 V ki
line par do bulb series mein lagao toh dono ko sirf 110-110 V milega aur dono
dhundhle jalenge.
Puraani Diwali ki jhaalar series mein hoti thi. Aur isiliye har saal wahi kahani hoti thi:
ek bulb fuse, poori jhaalar band — aur phir ek-ek bulb badal kar dekhna padta tha
ki kaunsa kharab hai!
Aaj ki LED jhaalar mein aksar chhote-chhote groups parallel mein jude hote hain —
isliye ek hissa kharab ho toh baaki jalte rehte hain.
Toh series kabhi kaam ka hai bhi? Haan!
🔹 Fuse hamesha series mein lagta hai — taaki wo poore circuit ka current rok
sake
🔹 Switch series mein lagta hai — usi wajah se wo circuit tod paata hai
🔹 Ammeter series mein lagta hai — taaki poora current usse guzre
Yani series ka istemaal wahan hota hai jahan aap
poore circuit ko ek saath control ya naapna chahte ho.
Gaon-dehat mein aksar dekha jaata hai ki log ek hi switch se kai cheezein chala lete hain, ya
ek socket par kai upkaran jod dete hain.
Yahan do alag baatein samajhna zaroori hai:
🔹 Ek socket par kai upkaran lagane ka matlab hai wo sab parallel mein hain — toh
har ek ko poora 220 V milta hai (theek), par kul current jud jaata hai. Agar wo
taar ki kshamata se zyada ho gaya toh taar garam hokar
aag pakad sakta hai.
🔹 Isiliye har line par sahi ampere ka fuse ya MCB — jo hamesha
series mein lagta hai — lagana zaroori hai.
Bharat mein har saal hazaron ghar short circuit se lagi aag mein jalte hain, aur
inme se zyadatar ki wajah yahi hoti hai: zyada load, patla taar, ya fuse ka na hona.
Ye ek lesson jo aap abhi padh rahe ho, sach mein jaan bacha sakta hai.
🧠 Apne Aap Ko Test Karo
🧊 3D Circuit Bench par series se parallel badlo aur farak khud dekho!
Open 3D Circuit Bench →